((4/x)+7)/((16/x^2)-49)

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Solution for ((4/x)+7)/((16/x^2)-49) equation: 


D( x )

x = 0

x^2 = 0

16/(x^2)-49 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

16/(x^2)-49 = 0

16/(x^2)-49 = 0

16*x^-2 = 49 // : 16

x^-2 = 49/16

-2 < 0

1/(x^2) = 49/16 // * x^2

1 = 49/16*x^2 // : 49/16

16/49 = x^2

x^2 = 16/49 // ^ 1/2

abs(x) = 4/7

x = 4/7 or x = -4/7

x in (-oo:-4/7) U (-4/7:0) U (0:4/7) U (4/7:+oo)

(4/x+7)/(16/(x^2)-49) = 0

(4*x^-1+7)/(16*x^-2-49) = 0

4*x^-1 = -7 // : 4

x^-1 = -7/4

-1 < 0

1/(x^1) = -7/4 // * x^1

1 = -7/4*x^1 // : -7/4

-4/7 = x^1

x = -4/7

x in { -4/7} 

x belongs to the empty set

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